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Mathematics
Mathematics
Problem
The velocity of a particle is
v
(
t
)
=
6
t
−
t
2
m/s
v(t)=6t-t^{2}\text{ m/s}
v
(
t
)
=
6
t
−
t
2
m/s
for
t
≥
0
t\ge 0
t
≥
0
. Find the value of
b
b
b
with
0
<
b
<
6
0<b<6
0
<
b
<
6
such that the particle’s average velocity on the interval
0
≤
t
≤
b
0\le t\le b
0
≤
t
≤
b
equals
3
m/s
3\text{ m/s}
3
m/s
.
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