Mathematics

Mathematics

Problem

The general solution of the differential equation, sin⁡2x(dydx−tan⁡x)−y=0\sin 2x \left( \frac{dy}{dx} - \sqrt{\tan x} \right) - y = 0 , is : [JEE-MAIN ONLINE] (1) ytan⁡x=cot⁡x+cy\sqrt{\tan x} = \cot x + c (2) ycot⁡x=x+cy\sqrt{\cot x} = x + c (3) ytan⁡x=x+cy\sqrt{\tan x} = x + c (4) ycot⁡x=tan⁡x+cy\sqrt{\cot x} = \tan x + c

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