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Mathematics
Problem
The general solution of the differential equation,
sin
2
x
(
d
y
d
x
−
tan
x
)
−
y
=
0
\sin 2x \left( \frac{dy}{dx} - \sqrt{\tan x} \right) - y = 0
sin
2
x
(
d
x
d
y
−
tan
x
)
−
y
=
0
, is : [JEE-MAIN ONLINE] (1)
y
tan
x
=
cot
x
+
c
y\sqrt{\tan x} = \cot x + c
y
tan
x
=
cot
x
+
c
(2)
y
cot
x
=
x
+
c
y\sqrt{\cot x} = x + c
y
cot
x
=
x
+
c
(3)
y
tan
x
=
x
+
c
y\sqrt{\tan x} = x + c
y
tan
x
=
x
+
c
(4)
y
cot
x
=
tan
x
+
c
y\sqrt{\cot x} = \tan x + c
y
cot
x
=
tan
x
+
c
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