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JEE Advanced 2017 Paper 2 Mathematics Q14
Mathematics
Problem
If
I
=
∑
k
=
1
98
∫
k
k
+
1
k
+
1
x
(
x
+
1
)
d
x
I=\displaystyle\sum_{k=1}^{98}\int_k^{k+1}\dfrac{k+1}{x(x+1)}\,dx
I
=
k
=
1
∑
98
∫
k
k
+
1
x
(
x
+
1
)
k
+
1
d
x
, then
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