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Mathematics
Mathematics
Problem
If
F
(
x
)
=
∫
1
x
f
(
t
)
d
t
F(x) = \int_{1}^{x} f(t) dt
F
(
x
)
=
∫
1
x
f
(
t
)
d
t
, where
f
(
t
)
=
∫
1
t
2
1
+
u
4
u
d
u
f(t) = \int_{1}^{t^2} \frac{\sqrt{1+u^4}}{u} du
f
(
t
)
=
∫
1
t
2
u
1
+
u
4
d
u
, then the value of
F
′
′
(
2
)
F''(2)
F
′′
(
2
)
equals to a.
7
4
17
\frac{7}{4\sqrt{17}}
4
17
7
b.
15
17
\frac{15}{\sqrt{17}}
17
15
c.
257
\sqrt{257}
257
d.
15
17
68
\frac{15\sqrt{17}}{68}
68
15
17
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