
Let a=4i^−j^+k^, b=11i^−j^+k^ and c be a vector such that (a+b)×c=c×(−2a+3b). If (2a+3b)⋅c=1670, then ∣c∣2 is equal to:
A 1609
B 1618
C 1600
D 1627