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Mathematics
Mathematics
Problem
A differentiable function
p
p
p
satisfies
p
′
(
x
)
=
4
−
2
x
p'(x)=4-2x
p
′
(
x
)
=
4
−
2
x
for
0
≤
x
≤
5
0 \le x \le 5
0
≤
x
≤
5
and the initial condition
p
(
0
)
=
1
p(0)=1
p
(
0
)
=
1
. Determine the absolute maximum value of
p
p
p
on the closed interval
[
0
,
5
]
[0,5]
[
0
,
5
]
and state the
x
x
x
-value at which it occurs.
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