Mathematics

Mathematics

Problem

A particle moves so that its velocity is v(t)=3t i+4 j+0 k\mathbf v(t)=3t\,\mathbf i+4\,\mathbf j+0\,\mathbf k. At t=1t=1, the particle is on the plane x−2y+z=5x-2y+z=5 at the point where y=1y=1. At what later time t>1t>1 does the particle next cross the same plane? a) t=4t=4 b) t=133t=\dfrac{13}{3} c) t=92t=\dfrac{9}{2} d) t=5t=5

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