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Problem
Problem
The least value of
α
∈
R
\alpha \in R
α
∈
R
for which
4
α
x
2
+
1
x
≥
1
4\alpha x^2 + \frac{1}{x} \ge 1
4
α
x
2
+
x
1
≥
1
, for all
x
>
0
x > 0
x
>
0
, is a.
1
64
\frac{1}{64}
64
1
b.
1
32
\frac{1}{32}
32
1
c.
1
27
\frac{1}{27}
27
1
d.
1
25
\frac{1}{25}
25
1
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