Mathematics

Mathematics

Problem

Determine the equation of the tangent line to the graph of y=arcsec⁡(2x)y=\operatorname{arcsec}(2x) at x=1x=1. a) y−π3=−13 (x−1)y-\dfrac{\pi}{3}=-\dfrac{1}{\sqrt{3}}\,(x-1) b) y−π3=13 (x−1)y-\dfrac{\pi}{3}=\dfrac{1}{\sqrt{3}}\,(x-1) c) y−π3=23 (x−1)y-\dfrac{\pi}{3}=\dfrac{2}{\sqrt{3}}\,(x-1) d) y−π3=3 (x−1)y-\dfrac{\pi}{3}=\sqrt{3}\,(x-1)

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