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JEE Advanced 2017 Paper 2 Mathematics Q2
Mathematics
Problem Let O O O be the origin and let P Q R PQR P QR be an arbitrary triangle. The point S S S is such that O P → ⋅ O Q → + O R → ⋅ O S → = O R → ⋅ O P → + O Q → ⋅ O S → = O Q → ⋅ O R → + O P → ⋅ O S → \overrightarrow{OP}\cdot\overrightarrow{OQ}+\overrightarrow{OR}\cdot\overrightarrow{OS}=\overrightarrow{OR}\cdot\overrightarrow{OP}+\overrightarrow{OQ}\cdot\overrightarrow{OS}=\overrightarrow{OQ}\cdot\overrightarrow{OR}+\overrightarrow{OP}\cdot\overrightarrow{OS} O P ⋅ O Q + O R ⋅ O S = O R ⋅ O P + O Q ⋅ O S = O Q ⋅ O R + O P ⋅ O S . Then the triangle P Q R PQR P QR has S S S as its
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