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Mathematics
Mathematics
Problem
Calculate the value of
4
∑
k
=
1
5
(
2
k
−
1
)
−
3
∑
k
=
1
5
2
k
−
1
4\displaystyle\sum_{k=1}^{5}(2k-1)\; -\; 3\displaystyle\sum_{k=1}^{5}2^{k-1}
4
k
=
1
∑
5
(
2
k
−
1
)
−
3
k
=
1
∑
5
2
k
−
1
.
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