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If
tan
(
π
12
−
x
)
,
tan
π
12
,
tan
(
π
12
+
x
)
\tan\left(\frac{\pi}{12} - x\right), \tan\frac{\pi}{12}, \tan\left(\frac{\pi}{12} + x\right)
tan
(
12
π
−
x
)
,
tan
12
π
,
tan
(
12
π
+
x
)
…
Mathematics
Problem
If
tan
(
π
12
−
x
)
,
tan
π
12
,
tan
(
π
12
+
x
)
\tan\left(\frac{\pi}{12} - x\right), \tan\frac{\pi}{12}, \tan\left(\frac{\pi}{12} + x\right)
tan
(
12
π
−
x
)
,
tan
12
π
,
tan
(
12
π
+
x
)
in order are three consecutive terms of a G.P. then sum of all the solutions in
[
0
,
314
]
[0, 314]
[
0
,
314
]
is
k
π
k\pi
k
π
. The value of
k
k
k
is : (a) 4950 (b) 5050 (c) 2525 (d) 5010
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