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›
Problems
Let
h
(
x
)
=
{
k
x
+
1
,
x
<
3
,
c
,
x
=
3
,
x
2
−
9
x
−
3
,
x
>
3.
h(x)=\begin{cases}kx+1, & x<3,\\[4pt]c, & x=3,\\[4pt]\dfrac{x^{2}-9}{x-3}, & x>3.\end{cases}
h
(
x
)
=
⎩
⎨
⎧
k
x
+
1
,
c
,
x
−
3
x
2
−
9
,
x
<
3
,
x
=
3
,
x
>
3.
…
Mathematics
Problem
Let
h
(
x
)
=
{
k
x
+
1
,
x
<
3
,
c
,
x
=
3
,
x
2
−
9
x
−
3
,
x
>
3.
h(x)=\begin{cases}kx+1, & x<3,\\[4pt]c, & x=3,\\[4pt]\dfrac{x^{2}-9}{x-3}, & x>3.\end{cases}
h
(
x
)
=
⎩
⎨
⎧
k
x
+
1
,
c
,
x
−
3
x
2
−
9
,
x
<
3
,
x
=
3
,
x
>
3.
Find the values of
k
k
k
and
c
c
c
that make
h
h
h
continuous at
x
=
3
x=3
x
=
3
.
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