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Problem
Problem
If no catalyst (
H
+
H^+
H
+
) is present in acid hydrolysis of ester then rate constant
k
k
k
is : (
V
V
V
is the volume of NaOH used during titration) (a)
2.303
t
log
V
0
[
V
t
−
V
∞
]
\frac{2.303}{t} \log \frac{V_0}{[V_t - V_\infty]}
t
2.303
lo
g
[
V
t
−
V
∞
]
V
0
(b)
2.303
t
log
V
∞
[
V
∞
−
V
t
]
\frac{2.303}{t} \log \frac{V_\infty}{[V_\infty - V_t]}
t
2.303
lo
g
[
V
∞
−
V
t
]
V
∞
(c)
2.303
t
log
V
0
V
t
\frac{2.303}{t} \log \frac{V_0}{V_t}
t
2.303
lo
g
V
t
V
0
(d)
2.303
t
log
V
∞
[
V
t
−
V
∞
]
\frac{2.303}{t} \log \frac{V_\infty}{[V_t - V_\infty]}
t
2.303
lo
g
[
V
t
−
V
∞
]
V
∞
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