sin⁡−1x+sin⁡−12x=2π3\sin^{-1} x + \sin^{-1} 2x = \frac{2\pi}{3}

Problem

sin⁡−1x+sin⁡−12x=2π3\sin^{-1} x + \sin^{-1} 2x = \frac{2\pi}{3}

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