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Mathematics
Problem
Solution of
∣
4
x
+
3
∣
+
∣
3
x
−
4
∣
=
12
|4x + 3| + |3x - 4| = 12
∣4
x
+
3∣
+
∣3
x
−
4∣
=
12
is : (A)
x
=
−
7
3
,
3
7
x = -\frac{7}{3}, \frac{3}{7}
x
=
−
3
7
,
7
3
(B)
x
=
−
5
2
,
2
5
x = -\frac{5}{2}, \frac{2}{5}
x
=
−
2
5
,
5
2
(C)
x
=
−
11
7
,
13
7
x = -\frac{11}{7}, \frac{13}{7}
x
=
−
7
11
,
7
13
(D)
x
=
−
3
7
,
7
5
x = -\frac{3}{7}, \frac{7}{5}
x
=
−
7
3
,
5
7
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