Physics

Physics

Problem

A vertical tube open to air is filled with an unknown liquid to a height of 0.80 m0.80\,\text{m}. The gauge at the base reads 6.3×103 Pa6.3\times10^3\,\text{Pa} above atmospheric pressure. Calculate the density of the liquid. (Take g=9.8 m s−2g = 9.8\,\text{m\,s}^{-2}.) a) 1.3×103 kg m−31.3\times10^{3}\,\text{kg\,m}^{-3} b) 8.0×102 kg m−38.0\times10^{2}\,\text{kg\,m}^{-3} c) 6.4×102 kg m−36.4\times10^{2}\,\text{kg\,m}^{-3} d) 1.0×103 kg m−31.0\times10^{3}\,\text{kg\,m}^{-3}

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