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Chemistry
Chemistry
Problem
E
R
P
∘
E_{RP}^\circ
E
R
P
∘
for the reaction,
TeO
3
2
−
(1M)
+
3
H
2
O (l)
+
4
e
⟶
Te (s)
+
6
OH
−
(aq)
\text{TeO}_3^{2-} \text{ (1M)} + 3\text{H}_2\text{O (l)} + 4e \longrightarrow \text{Te (s)} + 6\text{OH}^- \text{ (aq)}
TeO
3
2
−
(1M)
+
3
H
2
O (l)
+
4
e
⟶
Te (s)
+
6
OH
−
(aq)
is
−
0.57
V
-0.57 \text{ V}
−
0.57
V
. Calculate the potential of pH = 12. a.
−
0.17
V
-0.17 \text{ V}
−
0.17
V
b.
−
0.21
V
-0.21 \text{ V}
−
0.21
V
c.
−
0.39
V
-0.39 \text{ V}
−
0.39
V
d.
−
0.747
V
-0.747 \text{ V}
−
0.747
V
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