Mathematics

Mathematics

Problem

A differentiable function yy satisfies dydx=1x\dfrac{dy}{dx}=\dfrac{1}{x} and passes through the point (3,7)(3,7). A student writes the antiderivative y=ln⁡∣x∣+Cy=\ln|x|+C and then replaces ln⁡∣x∣\ln|x| with ln⁡x\ln x to obtain y=ln⁡x+Cy=\ln x+C. Which of the following statements best justifies this replacement? a) Because the constant CC can absorb any sign change, the absolute value bars are unnecessary. b) Because the initial condition requires x=3>0x=3>0, the particular solution is confined to x>0x>0, where ∣x∣=x|x|=x. c) Because the natural logarithm is defined for all real numbers, the absolute value bars may always be removed. d) Because ln⁡∣x∣\ln|x| and ln⁡x\ln x have the same derivative 1x\dfrac{1}{x} for x>0x>0, replacing ∣x∣|x| with xx is always valid.

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