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Mathematics
Mathematics
Problem
Solve the differential equation
(
1
+
y
2
)
(
1
+
log
x
)
d
x
+
x
d
y
=
0
,
it being given that
y
=
1
when
x
=
1.
(1 + y^2)(1 + \log x) dx + x dy = 0, \text{ it being given that } y = 1 \text{ when } x = 1.
(
1
+
y
2
)
(
1
+
lo
g
x
)
d
x
+
x
d
y
=
0
,
it being given that
y
=
1
when
x
=
1.
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