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JEE Advanced 2012 Paper 1 Mathematics Q6
Mathematics
Problem
The ellipse
E
1
:
x
2
9
+
y
2
4
=
1
E_1:\dfrac{x^2}{9}+\dfrac{y^2}{4}=1
E
1
:
9
x
2
+
4
y
2
=
1
is inscribed in a rectangle
R
R
R
whose sides are parallel to the coordinate axes. Another ellipse
E
2
E_2
E
2
passing through the point
(
0
,
4
)
(0,4)
(
0
,
4
)
circumscribes the rectangle
R
R
R
. The eccentricity of the ellipse
E
2
E_2
E
2
is
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