Physics

Physics

Problem

The position of a particle is recorded as follows: tt (s): 0,  4,  8,  120,\;4,\;8,\;12 xx (m): 0,  8,  −4,  −40,\;8,\;-4,\;-4 Consider three successive intervals: I. 0–4 s0\text{–}4\,\text{s}, II. 4–8 s4\text{–}8\,\text{s}, III. 8–12 s8\text{–}12\,\text{s}. Which option correctly gives the average velocities vI, vII, vIIIv_{\mathrm I},\,v_{\mathrm{II}},\,v_{\mathrm{III}}? a) vI=2 m s−1,  vII=3 m s−1,  vIII=0v_{\mathrm I}=2\,\text{m s}^{-1},\;v_{\mathrm{II}}=3\,\text{m s}^{-1},\;v_{\mathrm{III}}=0 b) vI=2 m s−1,  vII=−3 m s−1,  vIII=1 m s−1v_{\mathrm I}=2\,\text{m s}^{-1},\;v_{\mathrm{II}}=-3\,\text{m s}^{-1},\;v_{\mathrm{III}}=1\,\text{m s}^{-1} c) vI=2 m s−1,  vII=−3 m s−1,  vIII=0v_{\mathrm I}=2\,\text{m s}^{-1},\;v_{\mathrm{II}}=-3\,\text{m s}^{-1},\;v_{\mathrm{III}}=0 d) vI=3 m s−1,  vII=−2 m s−1,  vIII=0v_{\mathrm I}=3\,\text{m s}^{-1},\;v_{\mathrm{II}}=-2\,\text{m s}^{-1},\;v_{\mathrm{III}}=0

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