Blundell Thermal Physics · Problem 17.5

Rods, bubbles, and magnets

Physics — Statistical Mechanics · surface-tension-molecular-energy

Problem

Consider a liquid of density ρ\rho with molar mass MM. Explain why the number of molecules per unit area in the surface is approximately (ρNA/M)2/3.\left(\rho N_\mathrm{A}/M\right)^{2/3}. Hence, the energy contribution per molecule to the surface tension γ\gamma is approximately γ/(ρNA/M)2/3.\gamma / \left(\rho N_\mathrm{A}/M\right)^{2/3}. Evaluate this quantity for water (surface tension at 20 ∘C20\,^\circ\mathrm{C} is approximately 72 mJ m−272\,\mathrm{mJ\,m^{-2}}) and express your answer in eV. Compare your result with the latent heat per molecule (the molar latent heat of water is 4.4×104 J mol−14.4 \times 10^4\,\mathrm{J\,mol^{-1}}).

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