Mathematics

Mathematics

Problem

∫dx1+3sin⁡2x=\int \frac{dx}{1+3\sin^2 x} = (a) 13tan⁡−1(3tan⁡2x)+c\frac{1}{3} \tan^{-1}(3 \tan^2 x) + c (b) 12tan⁡−1(2tan⁡x)+c\frac{1}{2} \tan^{-1}(2 \tan x) + c (c) tan⁡−1(tan⁡x)+c\tan^{-1}(\tan x) + c (d) None of these (a) 13tan⁡−1(3tan⁡2x)+c\frac{1}{3} \tan^{-1}(3 \tan^2 x) + c (b) 12tan⁡−1(2tan⁡x)+c\frac{1}{2} \tan^{-1}(2 \tan x) + c (c) tan⁡−1(tan⁡x)+c\tan^{-1}(\tan x) + c (d) None of these

Browse the problem library