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Mathematics
Problem
Let
r
1
(
θ
)
=
2
sin
θ
r_1(\theta)=2\sin\theta
r
1
(
θ
)
=
2
sin
θ
and
r
2
(
θ
)
=
sin
θ
+
1
r_2(\theta)=\sin\theta+1
r
2
(
θ
)
=
sin
θ
+
1
. These curves enclose a finite region that lies entirely in the first quadrant. What is the exact area of this region? a)
π
8
−
1
\dfrac{\pi}{8}-1
8
π
−
1
b)
2
−
π
4
2-\dfrac{\pi}{4}
2
−
4
π
c)
1
−
π
8
1-\dfrac{\pi}{8}
1
−
8
π
d)
3
π
8
−
1
\dfrac{3\pi}{8}-1
8
3
π
−
1
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