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Mathematics
Problem
If the volume of a spherical ball is increasing at the rate of
4
π
4\pi
4
π
cc/sec, then the rate of increase of its radius (in cm/sec), when the volume is
288
π
288\pi
288
π
cc, is : [JEE-MAIN ONLINE-2014] (1)
1
24
\frac{1}{24}
24
1
(2)
1
6
\frac{1}{6}
6
1
(3)
1
9
\frac{1}{9}
9
1
(4)
1
36
\frac{1}{36}
36
1
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