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Mathematics
Mathematics
Problem
The slope of tangent to the curve
x
=
t
2
+
3
t
−
8
x = t^2 + 3t - 8
x
=
t
2
+
3
t
−
8
and
y
=
2
t
2
−
2
t
−
5
y = 2t^2 - 2t - 5
y
=
2
t
2
−
2
t
−
5
at the point
(
2
,
−
1
)
(2, -1)
(
2
,
−
1
)
is (a)
22
7
\frac{22}{7}
7
22
(b)
6
7
\frac{6}{7}
7
6
(c)
−
6
7
-\frac{6}{7}
−
7
6
(d)
−
6
-6
−
6
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