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Mathematics
Mathematics
Problem
The function
p
p
p
is defined by
p
(
x
)
=
x
2
−
1
x
−
1
p(x)=\dfrac{x^{2}-1}{x-1}
p
(
x
)
=
x
−
1
x
2
−
1
for
x
≠
1
x\ne 1
x
=
1
and
p
(
1
)
=
2
p(1)=2
p
(
1
)
=
2
. Determine
p
′
(
1
)
p'(1)
p
′
(
1
)
. a)
0
0
0
b)
2
2
2
c)
1
1
1
d) The derivative does not exist at
x
=
1
x=1
x
=
1
.
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