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Problem
Problem
If
Δ
\Delta
Δ
represents the area of acute angled triangle ABC, then
a
2
b
2
−
4
Δ
2
+
b
2
c
2
−
4
Δ
2
+
c
2
a
2
−
4
Δ
2
\sqrt{a^2b^2 - 4\Delta^2} + \sqrt{b^2c^2 - 4\Delta^2} + \sqrt{c^2a^2 - 4\Delta^2}
a
2
b
2
−
4
Δ
2
+
b
2
c
2
−
4
Δ
2
+
c
2
a
2
−
4
Δ
2
is equal to a.
a
2
+
b
2
+
c
2
a^2 + b^2 + c^2
a
2
+
b
2
+
c
2
b.
a
2
+
b
2
+
c
2
2
\frac{a^2 + b^2 + c^2}{2}
2
a
2
+
b
2
+
c
2
c.
a
b
cos
C
+
b
c
cos
A
+
c
a
cos
B
ab \cos C + bc \cos A + ca \cos B
ab
cos
C
+
b
c
cos
A
+
c
a
cos
B
d.
a
b
sin
C
+
b
c
sin
A
+
c
a
sin
B
ab \sin C + bc \sin A + ca \sin B
ab
sin
C
+
b
c
sin
A
+
c
a
sin
B
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