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Chemistry
Chemistry
Problem
Equivalent mass of nitrogen in the reaction :
(
NH
4
)
2
Cr
2
O
7
⟶
N
2
+
Cr
2
O
3
+
4
H
2
O
(\text{NH}_4)_2\text{Cr}_2\text{O}_7 \longrightarrow \text{N}_2 + \text{Cr}_2\text{O}_3 + 4\text{H}_2\text{O}
(
NH
4
)
2
Cr
2
O
7
⟶
N
2
+
Cr
2
O
3
+
4
H
2
O
is
M
X
\frac{M}{X}
X
M
. The value of
X
X
X
is .....
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