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Mathematics
Mathematics
Problem
Let
h
h
h
be a twice–differentiable function such that
h
′
(
x
)
=
sin
x
h'(x)=\sin x
h
′
(
x
)
=
sin
x
for
0
≤
x
≤
2
π
0\le x\le 2\pi
0
≤
x
≤
2
π
and
h
(
0
)
=
1
h(0)=1
h
(
0
)
=
1
. At which value of
x
x
x
in the interval
(
0
,
2
π
)
(0,2\pi)
(
0
,
2
π
)
does
h
h
h
attain a relative maximum? a)
x
=
3
π
2
x=\dfrac{3\pi}{2}
x
=
2
3
π
b)
x
=
π
x=\pi
x
=
π
c)
x
=
2
π
x=2\pi
x
=
2
π
d)
x
=
π
2
x=\dfrac{\pi}{2}
x
=
2
π
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