Physics

Physics · thermodynamics

Problem

2.6 If this spherical bubble is now electrified uniformly with a total charge qq, find an equation describing the new radius R1R_{1} in terms of R0,Pa,qR_{0}, P_{a}, q and the permittivity of free space ε0\varepsilon_{0}. Given constants: An Electrified Soap Bubble A spherical soap bubble with internal air density ρi\rho_{i}, temperature TiT_{i} and radius R0R_{0} is surrounded by air with density ρa\rho_{a}, atmospheric pressure PaP_{a} and temperature TaT_{a}. The soap film has surface tension γ\gamma, density ρs\rho_{s} and thickness tt. The mass and the surface tension of the soap do not change with the temperature. Assume that R0≫tR_{0} \gg t. The increase in energy, dEd E, that is needed to increase the surface area of a soap-air interface by dAd A, is given by dE=γdAd E=\gamma d A where γ\gamma is the surface tension of the film. Context question: 2.1 Find the ratio ρiTiρaTa\frac{\rho_{i} T_{i}}{\rho_{a} T_{a}} in terms of γ,Pa\gamma, P_{a} and R0R_{0}. Context answer: 1+4γR0Pa1+\frac{4 \gamma}{R_{0} P_{a}} Context question: 2.2 Find the numerical value of ρiTiρaTa−1\frac{\rho_{i} T_{i}}{\rho_{a} T_{a}}-1 using γ=0.0250Nm−1,R0=1.00 cm\gamma=0.0250 \mathrm{Nm}^{-1}, R_{0}=1.00 \mathrm{~cm}, and Pa=1.013×105Nm−2P_{a}=1.013 \times 10^{5} \mathrm{Nm}^{-2}. Context answer: 1.0001 Context question: 2.3 The bubble is initially formed with warmer air inside. Find the minimum numerical value of TiT_{i} such that the bubble can float in still air. Use Ta=300 K,ρs=1000kgm−3T_{a}=300 \mathrm{~K}, \rho_{s}=1000 \mathrm{kgm}^{-3}, ρa=1.30kgm−3,t=100 nm\rho_{a}=1.30 \mathrm{kgm}^{-3}, t=100 \mathrm{~nm} and g=9.80 ms−2g=9.80 \mathrm{~ms}^{-2}. Context answer: 307.1 Extra Supplementary Reading Materials: After the bubble is formed for a while, it will be in thermal equilibrium with the surrounding. This bubble in still air will naturally fall towards the ground. Context question: 2.4 Find the minimum velocity uu of an updraught (air flowing upwards) that will keep the bubble from falling at thermal equilibrium. Give your answer in terms of ρs,R0,g,t\rho_{s}, R_{0}, g, t and the air's coefficient of viscosity η\eta. You may assume that the velocity is small such that Stokes's law applies, and ignore the change in the radius when the temperature lowers to the equilibrium. The drag force from Stokes' Law is F=6πηR0uF=6 \pi \eta R_{0} u. Context answer: 4R0ρstg6η+43R02ρag(4γR0Pa)6η\frac{4 R_{0} \rho_{s} t g}{6 \eta}+\frac{\frac{4}{3} R_{0}^{2} \rho_{a} g\left(\frac{4 \gamma}{R_{0} P_{a}}\right)}{6 \eta} Context question: 2.5 Calculate the numerical value for uu using η=1.8×10−5kgm−1 s−1\eta=1.8 \times 10^{-5} \mathrm{kgm}^{-1} \mathrm{~s}^{-1}. Context answer: 0.360.36 Extra Supplementary Reading Materials: The above calculations suggest that the terms involving the surface tension γ\gamma add very little to the accuracy of the result. In all of the questions below, you can neglect the surface tension terms.

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