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Mathematics
Problem
Let
G
(
x
)
=
∫
0
x
(
t
3
+
1
)
d
t
G(x)=\displaystyle \int_{0}^{\sqrt{x}}\!(t^{3}+1)\,dt
G
(
x
)
=
∫
0
x
(
t
3
+
1
)
d
t
for
x
>
0
x>0
x
>
0
. Determine the value of
G
′
(
4
)
G'(4)
G
′
(
4
)
.
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