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Mathematics
Mathematics
Problem
If
sin
(
90
∘
−
θ
)
=
3
5
\sin(90^\circ-\theta)=\dfrac{3}{5}
sin
(
9
0
∘
−
θ
)
=
5
3
for an acute angle
θ
\theta
θ
, then
tan
θ
\tan\theta
tan
θ
equals a)
3
5
\dfrac{3}{5}
5
3
b)
4
3
\dfrac{4}{3}
3
4
c)
3
4
\dfrac{3}{4}
4
3
d)
5
3
\dfrac{5}{3}
3
5
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