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Mathematics
Problem
If two points
P
P
P
and
Q
Q
Q
on the hyperbola
x
2
a
2
−
y
2
b
2
=
1
\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1
a
2
x
2
−
b
2
y
2
=
1
whose centre is
C
C
C
, are such that
C
P
CP
C
P
is perpendicular to
C
Q
CQ
C
Q
,
a
<
b
a < b
a
<
b
, then prove that
1
(
C
P
)
2
+
1
(
C
Q
)
2
=
1
a
2
−
1
b
2
\frac{1}{(CP)^2} + \frac{1}{(CQ)^2} = \frac{1}{a^2} - \frac{1}{b^2}
(
C
P
)
2
1
+
(
C
Q
)
2
1
=
a
2
1
−
b
2
1
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