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Mathematics
Mathematics
Problem
Number of solutions of equation
tan
−
1
(
e
−
x
)
+
cot
−
1
(
∣
ln
x
∣
)
=
π
/
2
\tan^{-1}(e^{-x}) + \cot^{-1}(|\ln x|) = \pi/2
tan
−
1
(
e
−
x
)
+
cot
−
1
(
∣
ln
x
∣
)
=
π
/2
is: (a) 0 (b) 1 (c) 3 (d) 2
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