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Physics
Physics
Problem
Calculate the Q-value (in MeV) for the alpha-decay
92
238
U
→
90
234
T
h
+
2
4
H
e
.
^{238}_{\;92}\mathrm{U}\;\rightarrow\;^{234}_{\;90}\mathrm{Th}+^{4}_{2}\mathrm{He}.
92
238
U
→
90
234
Th
+
2
4
He
.
Atomic masses:
238
U
=
238.050788
u
^{238}\mathrm{U}=238.050788\,\text{u}
238
U
=
238.050788
u
,
234
T
h
=
234.043593
u
^{234}\mathrm{Th}=234.043593\,\text{u}
234
Th
=
234.043593
u
,
4
H
e
=
4.002603
u
^{4}\mathrm{He}=4.002603\,\text{u}
4
He
=
4.002603
u
. Take
1
u
=
931.5
MeV
/
c
2
1\,\text{u}=931.5\,\text{MeV}/c^{2}
1
u
=
931.5
MeV
/
c
2
.
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