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Mathematics
Mathematics
Problem
Find
d
d
x
[
(
2
x
3
−
1
)
5
]
\displaystyle \frac{d}{dx}\big[(2x^{3}-1)^{5}\big]
d
x
d
[
(
2
x
3
−
1
)
5
]
. a)
15
x
2
(
2
x
3
−
1
)
4
15x^{2}(2x^{3}-1)^{4}
15
x
2
(
2
x
3
−
1
)
4
b)
30
x
2
(
2
x
3
−
1
)
5
30x^{2}(2x^{3}-1)^{5}
30
x
2
(
2
x
3
−
1
)
5
c)
30
x
2
(
2
x
3
−
1
)
4
30x^{2}(2x^{3}-1)^{4}
30
x
2
(
2
x
3
−
1
)
4
d)
5
(
2
x
3
−
1
)
4
5(2x^{3}-1)^{4}
5
(
2
x
3
−
1
)
4
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