The equations of two sides AB and AC of a triangle ABC are 4x+y=14 and 3x−2y=5, respectively. The point (2,−34) divides the third side BC internally in the ratio 2:1, the equation of the side BC is
(a) x+3y+2=0
(b) x−3y−6=0
(c) x+6y+6=0
(d) x−6y−10=0