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Mathematics
Mathematics
Problem
Show that the two values
x
=
−
b
±
b
2
−
4
a
c
2
a
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
x
=
2
a
−
b
±
b
2
−
4
a
c
are the roots of the equation
a
x
2
+
b
x
+
c
=
0
ax^2 + bx + c = 0
a
x
2
+
b
x
+
c
=
0
, where
a
a
a
,
b
b
b
, and
c
c
c
are constants, and
a
a
a
and
c
c
c
are nonzero.
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