Mathematics

Mathematics

Problem

For x>1x>1, let y=arcsec⁡xy=\operatorname{arcsec} x. Which of the following is the correct formula for dydx\dfrac{dy}{dx}? a) −1xx2−1-\dfrac{1}{x\sqrt{x^{2}-1}} b) 1xx2−1\dfrac{1}{x\sqrt{x^{2}-1}} c) 1x2−1\dfrac{1}{\sqrt{x^{2}-1}} d) 1xx2+1\dfrac{1}{x\sqrt{x^{2}+1}}

Browse the problem library