Lebl-Basic-Analysis-I · Problem 3.2.19

Continuous Functions

Mathematics · continuous-functions

Problem

(Challenging) A function f:I→Rf : I \to \mathbb{R} is convex if whenever a≤x≤ba \leq x \leq b for a,x,ba, x, b in II, we have f(x)≤f(a)b−xb−a+f(b)x−ab−af(x) \leq f(a)\dfrac{b-x}{b-a} + f(b)\dfrac{x-a}{b-a}. In other words, if the line drawn between (a,f(a))\bigl(a, f(a)\bigr) and (b,f(b))\bigl(b, f(b)\bigr) is above the graph of ff. a) Prove that if I=(α,β)I = (\alpha, \beta) an open interval and f:I→Rf : I \to \mathbb{R} is convex, then ff is continuous. b) Find an example of a convex f:[0,1]→Rf : [0, 1] \to \mathbb{R} that is not continuous.

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