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Mathematics
Problem
∫
1
x
1
+
log
x
d
x
=
\int \frac{1}{x\sqrt{1+\log x}}\,dx =
∫
x
1
+
l
o
g
x
1
d
x
=
A)
2
3
(
1
+
log
x
)
3
/
2
+
c
\frac{2}{3}(1+\log x)^{3/2} + c
3
2
(
1
+
lo
g
x
)
3/2
+
c
B)
(
1
+
log
x
)
3
/
2
+
c
(1+\log x)^{3/2} + c
(
1
+
lo
g
x
)
3/2
+
c
C)
2
1
+
log
x
+
c
2\sqrt{1+\log x} + c
2
1
+
lo
g
x
+
c
D)
1
+
log
x
+
c
\sqrt{1+\log x} + c
1
+
lo
g
x
+
c
A)
2
3
(
1
+
log
x
)
3
/
2
+
c
\frac{2}{3}(1+\log x)^{3/2} + c
3
2
(
1
+
lo
g
x
)
3/2
+
c
B)
(
1
+
log
x
)
3
/
2
+
c
(1+\log x)^{3/2} + c
(
1
+
lo
g
x
)
3/2
+
c
C)
2
1
+
log
x
+
c
2\sqrt{1+\log x} + c
2
1
+
lo
g
x
+
c
D)
1
+
log
x
+
c
\sqrt{1+\log x} + c
1
+
lo
g
x
+
c
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