I=∫018log⁡(1+x)(1+x2)dxI = \int_0^1 \frac{8 \log(1+x)}{(1+x^2)} dx

Mathematics

Problem

I=∫018log⁡(1+x)(1+x2)dxI = \int_0^1 \frac{8 \log(1+x)}{(1+x^2)} dx

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