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Mathematics
Mathematics
Problem
Compute the sum of the series
∑
n
=
0
∞
[
3
(
1
2
)
n
+
4
(
−
1
3
)
n
]
\displaystyle \sum_{n=0}^{\infty} \left[3\left(\dfrac12\right)^{n}+4\left(-\dfrac13\right)^{n}\right]
n
=
0
∑
∞
[
3
(
2
1
)
n
+
4
(
−
3
1
)
n
]
. a)
12
12
12
b)
2
2
2
c)
9
9
9
d)
−
3
-3
−
3
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