Consider k(x)=exx2+xcosx. Which statement about the horizontal asymptote(s) of k is correct?
a) k has no horizontal asymptotes because the term exx2 grows without bound.
b) k has a horizontal asymptote y=0 for both x→+∞ and x→−∞.
c) k has a single horizontal asymptote y=0 as x→+∞, but none as x→−∞.
d) k has no horizontal asymptotes because the term xcosx continues to oscillate.