Basic Analysis I — Real Analysis · Problem 5.4.10

The Riemann Integral — Jiri Lebl

Mathematics — Real Analysis · uniqueness-exponential-logarithm

Problem

Show that E(x)=exE(x) = e^x is the unique continuous function such that E(x+y)=E(x)E(y)E(x+y) = E(x)E(y) and E(1)=eE(1) = e. Similarly, prove that L(x)=ln⁡(x)L(x) = \ln(x) is the unique continuous function defined on positive xx such that L(xy)=L(x)+L(y)L(xy) = L(x) + L(y) and L(e)=1L(e) = 1.

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