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Mathematics
Mathematics
Problem
The value of
∫
−
1
1
log
(
2
−
x
2
+
x
)
d
x
\int_{-1}^{1} \log \left( \frac{2-x}{2+x} \right) dx
∫
−
1
1
lo
g
(
2
+
x
2
−
x
)
d
x
is equal to a.
1
2
\frac{1}{2}
2
1
b. 1 c. -1 d. 0
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