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Mathematics
Mathematics
Problem
If the circles
x
2
+
y
2
+
2
x
+
2
k
y
+
6
=
0
x^2 + y^2 + 2x + 2ky + 6 = 0
x
2
+
y
2
+
2
x
+
2
k
y
+
6
=
0
and
x
2
+
y
2
+
2
k
y
+
k
=
0
x^2 + y^2 + 2ky + k = 0
x
2
+
y
2
+
2
k
y
+
k
=
0
intersect orthogonally,
k
k
k
is a. 2 or
−
3
2
-\frac{3}{2}
−
2
3
b.
−
2
-2
−
2
or
−
3
2
-\frac{3}{2}
−
2
3
c. 2 or
3
2
\frac{3}{2}
2
3
d.
−
2
-2
−
2
or
3
2
\frac{3}{2}
2
3
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