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Mathematics
Mathematics
Problem
The equations of perpendicular bisectors of two sides AB & AC of a triangle ABC are
x
+
y
+
1
=
0
x + y + 1 = 0
x
+
y
+
1
=
0
and
x
−
y
+
1
=
0
x - y + 1 = 0
x
−
y
+
1
=
0
respectively. If circumradius of
Δ
A
B
C
\Delta ABC
Δ
A
B
C
is 2 units and the locus of vertex A is
x
2
+
y
2
+
g
x
+
c
=
0
x^2 + y^2 + gx + c = 0
x
2
+
y
2
+
g
x
+
c
=
0
then
g
2
+
c
2
g^2 + c^2
g
2
+
c
2
equals : A. 4 B. 5 C. 9 D. 13
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